5x^2+19x=-20

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Solution for 5x^2+19x=-20 equation: 



5x^2+19x=-20

We move all terms to the left:

5x^2+19x-(-20)=0

We add all the numbers together, and all the variables

5x^2+19x+20=0

a = 5; b = 19; c = +20;
Δ = b2-4ac
Δ = 192-4·5·20
Δ = -39
Delta is less than zero, so there is no solution for the equation

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